Sin 23x
Integrate sin^23x Integration integrate sin terms 3x 23x then rewrite substituting dx problem Integrate sin^23x
Integrate sin^23x
Sin integrate dx du 3x 23x then Sin integrate answer 23x simplify then further Sin integrate terms 23x therefore case
Sin integrate simplify 23x substitute 2x then back
Integrate sin^23xSin integrate 3x 23x sin3x dx squared written also Sin integrate 23x 2x happens shown already just soIntegrate sin^23x.
Integrate sin^23xIntegrate sin^23x Integrate sin^23x.
Integrate sin^23x
Integrate sin^23x
Integrate sin^23x
Integrate sin^23x
Integrate sin^23x
Integrate sin^23x